What is the output of the following program?
#include<stdio.h>
int c[10] = {1,2,3,4,5,6,7,8,9,10};
main()
{
int a, b=0;
for(a=0;a<10;++a)
if(c[a]%2 == 1)
b+=c[a];
printf("%d", b);
}

Question

What is the output of the following program?

#include<stdio.h>
int c[10] = {1,2,3,4,5,6,7,8,9,10};
main()
{
int a, b=0;
for(a=0;a<10;++a)
if(c[a]%2 == 1)
b+=c[a];
printf("%d", b);
}

a)
20
b)
24
c)
25
d)
30

Correct answer is option 'C'. Can you explain this answer?

Answer

Explanation:

Initial Array:
- The initial array c contains values from 1 to 10.

Loop:
- The for loop iterates through each element of the array c.
- It checks if the current element is odd (since it checks if c[a] % 2 == 1).
- If the element is odd, it adds the element to the variable b.

Calculations:
- In the array c, the odd numbers are 1, 3, 5, 7, 9.
- Adding these odd numbers (1 + 3 + 5 + 7 + 9) gives the result 25.

Output:
- The final result stored in variable b is 25.
- Therefore, when the program is executed, it will output 25.

Answer

Condition if(c[a]%2 == 1) forces only odd numbers to add in the sum.

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